Matematika

7-sinf · Algebra · 25 daqiqa

Natural ko'rsatkichli daraja

Algebraik ifodalar: mavzular

Bu nima va nega kerak

Bakteriyalar har soatda ikki baravarga ko'payadi. 1 ta bakteriya bor edi. 10 soatdan keyin nechta bo'ladi?

Hisoblaymiz: 1⋅2⋅2⋅2⋯1 \cdot 2 \cdot 2 \cdot 2 \cdots (10 marta) =210=1024= 2^{10} = 1024.

Agar daraja tushunchasi bo'lmasa, bu sonni yozish qiyin. Daraja — bir xil ko'paytuvchini qayta-qayta yozmaslik uchun qulay yozuv.

Fizikada maydon S=a2S = a^2, hajm V=a3V = a^3, yorug'lik tezligi c=3×108c = 3\times10^8 m/s — bularning hammasi daraja. DTMda daraja va uning xossalarini bilmasdan ko'plab masalalarni yechib bo'lmaydi.

Asosiy g'oya

Ta'rif. aa ning natural nn ko'rsatkichli darajasi — aa ni nn marta o'z-o'ziga ko'paytirish:

an=a⋅a⋅a⋯a⏟n ta.a^n = \underbrace{a \cdot a \cdot a \cdots a}_{n \text{ ta}}.

Bu yerda aa — asos, nn — ko'rsatkich (daraja ko'rsatkichi).

Maxsus holatlar:

  • a1=aa^1 = a
  • a0=1a^0 = 1 (nolga teng bo'lmagan har qanday aa uchun)

Darajaning xossalari (a≠0a \neq 0, m,nm, n — natural sonlar):

XossaFormula
Ko'paytirisham⋅an=am+na^m \cdot a^n = a^{m+n}
Bo'lishaman=am−n\dfrac{a^m}{a^n} = a^{m-n}
Darajani darajaga ko'tarish(am)n=am⋅n(a^m)^n = a^{m\cdot n}
Ko'paytmaning darajasi(ab)n=anbn(ab)^n = a^n b^n
Kasrning darajasi(ab)n=anbn\left(\dfrac{a}{b}\right)^n = \dfrac{a^n}{b^n}

Muhim: Bu xossalar faqat bir xil asosga ega darajalar uchun ishlaydi (am⋅ana^m \cdot a^n). Turli asoslar (am⋅bna^m \cdot b^n) bevosita qo'shilmaydi.

Yechilgan misollar

1-misol. Darajani hisoblash

343^4 ni hisoblang.

  • 34=3⋅3⋅3⋅3=9⋅9=813^4 = 3 \cdot 3 \cdot 3 \cdot 3 = 9 \cdot 9 = 81.

Javob: 81.

Qo'shimcha: 34≠3⋅4=123^4 \neq 3 \cdot 4 = 12. Ko'paytirish va daraja — farqli amallar!


2-misol. Ko'paytirish xossasi

x5⋅x3x^5 \cdot x^3 ni soddalashtiring.

  • Asoslar bir xil (xx), ko'rsatkichlarni qo'shamiz: x5+3=x8x^{5+3} = x^8.

Javob: x8x^8.


3-misol. Darajani darajaga ko'tarish va ko'paytmaning darajasi

(2a3)4(2a^3)^4 ni hisoblang.

  • Ko'paytmaning darajasi: (2a3)4=24⋅(a3)4(2a^3)^4 = 2^4 \cdot (a^3)^4.
  • 24=162^4 = 16.
  • (a3)4=a3⋅4=a12(a^3)^4 = a^{3 \cdot 4} = a^{12}.
  • Jami: 16a1216a^{12}.

Javob: 16a1216a^{12}.


4-misol. Manfiy asos va daraja

(−3)3(-3)^3 va (−3)4(-3)^4 ni hisoblang.

  • (−3)3=(−3)⋅(−3)⋅(−3)=9⋅(−3)=−27(-3)^3 = (-3)\cdot(-3)\cdot(-3) = 9\cdot(-3) = -27. Toq ko'rsatkich → manfiy.
  • (−3)4=(−3)⋅(−3)⋅(−3)⋅(−3)=9⋅9=81(-3)^4 = (-3)\cdot(-3)\cdot(-3)\cdot(-3) = 9 \cdot 9 = 81. Juft ko'rsatkich → musbat.

Qoida: Manfiy sonning:

  • juft ko'rsatkichli darajasi — musbat;
  • toq ko'rsatkichli darajasi — manfiy.

5-misol. Darajalar bilan ifodani soddalashtirish

a6⋅a2a3\dfrac{a^6 \cdot a^2}{a^3} ni soddalashtiring (a≠0a \neq 0).

  • Avval suratni: a6⋅a2=a8a^6 \cdot a^2 = a^8.
  • Keyin bo'lamiz: a8a3=a8−3=a5\dfrac{a^8}{a^3} = a^{8-3} = a^5.

Javob: a5a^5.


Mashq

  1. 535^3 ni hisoblang.
  2. 262^6 ni hisoblang.
  3. (−1)101(-1)^{101} ni hisoblang.
  4. a4⋅a7a^4 \cdot a^7 ni soddalashtiring.
  5. b10b4\dfrac{b^{10}}{b^4} ni soddalashtiring (b≠0b \neq 0).
  6. (x2)5(x^2)^5 ni soddalashtiring.
  7. (3b)3(3b)^3 ni oching.
  8. (a2)4\left(\dfrac{a}{2}\right)^4 ni hisoblang.
  9. 23⋅22÷242^3 \cdot 2^2 \div 2^4 ni soddalashtiring.
  10. (−2)3+(−2)4(-2)^3 + (-2)^4 ni hisoblang.
Javoblar va yechim yo'llari
  1. 5⋅5⋅5=1255\cdot5\cdot5 = 125.
  2. 2⋅2⋅2⋅2⋅2⋅2=642\cdot2\cdot2\cdot2\cdot2\cdot2 = 64.
  3. (−1)101=−1(-1)^{101} = -1 (toq ko'rsatkich).
  4. a4+7=a11a^{4+7} = a^{11}.
  5. b10−4=b6b^{10-4} = b^6.
  6. x2⋅5=x10x^{2\cdot5} = x^{10}.
  7. 33⋅b3=27b33^3 \cdot b^3 = 27b^3.
  8. a424=a416\dfrac{a^4}{2^4} = \dfrac{a^4}{16}.
  9. 23+2−4=21=22^{3+2-4} = 2^1 = 2.
  10. (−8)+16=8(-8) + 16 = 8.

Keng tarqalgan xatolar

1. Darajani ko'paytirish bilan aralashtirish. ✗ 34=3⋅4=123^4 = 3 \cdot 4 = 12. ✓ 34=3⋅3⋅3⋅3=813^4 = 3 \cdot 3 \cdot 3 \cdot 3 = 81.

2. Turli asosli darajalarning ko'rsatkichlarini qo'shish. ✗ a3⋅b2=ab5a^3 \cdot b^2 = ab^5. ✓ a3⋅b2a^3 \cdot b^2 — bu allaqacha sodda, qo'shib bo'lmaydi.

3. Manfiy soning darajasida qavsni tushirish. ✗ −32=(−3)2=9-3^2 = (-3)^2 = 9. ✓ −32=−(32)=−9-3^2 = -(3^2) = -9, lekin (−3)2=9(-3)^2 = 9. Farq bor!

4. Ko'rsatkichni ko'paytmaga ko'chirishni unutish. ✗ (2a)3=2a3(2a)^3 = 2a^3. ✓ (2a)3=23⋅a3=8a3(2a)^3 = 2^3 \cdot a^3 = 8a^3.

5. a0=0a^0 = 0 deyish. ✗ 50=05^0 = 0. ✓ 50=15^0 = 1 (har qanday noldan farqli aa da a0=1a^0 = 1).

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Keyingi qadam

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Test

0 / 5 javob berildi

  1. 1.252^5 ning qiymati?

  2. 2.a3⋅a4a^3 \cdot a^4 ni soddalashtiring.

  3. 3.(3a2)3(3a^2)^3 ni hisoblang.

  4. 4.x8x3\dfrac{x^8}{x^3} ni soddalashtiring (x≠0x\neq0).

  5. 5.(−2)4(-2)^4 qancha?