Matematika

7-sinf · Algebra · 25 daqiqa

Ko'phadlar, qo'shish va ayirish

Algebraik ifodalar: mavzular

Bu nima va nega kerak

Do'konda narx-navo o'zgaradi: bug'doy narxi 3p+1003p + 100 so'm, sholi narxi 2p−502p - 50 so'm (bu yerda pp — bozor indeksi). Jami xarajat qancha? Ikki harfli ifodani qo'shish kerak.

Ko'phadlar — kundalik hayotdagi o'zgaruvchan kattaliklar modelidir. Fizikada jism yo'li s=v0t+at22s = v_0t + \dfrac{at^2}{2} — bu uch hadli ko'phad. Daromad, foyda, masofa — hammasi ko'phadlar yordamida hisoblanadi. Ularni qo'sha va ayira bilish — keyingi barcha algebra mavzularining asosi.

Asosiy g'oya

Ta'rif. Birhadlarning algebraik yig'indisi ko'phad deyiladi. Har bir birhad ko'phadning hadi deyiladi.

Misollar:

  • 5x+35x + 3 — ikki hadli (binomial)
  • a2−2ab+b2a^2 - 2ab + b^2 — uch hadli (trinomial)
  • 3x4−x2+2x−73x^4 - x^2 + 2x - 7 — to'rt hadli

Ko'phadning darajasi — eng katta darajali hadning darajasi. Masalan, 4x3−x+24x^3 - x + 2 ning darajasi 33.

Standart ko'rinish — ko'phadning hadlari darajasi kamayish tartibida yoziladi: 3x4−2x3+x−5.3x^4 - 2x^3 + x - 5.

Ko'phadlarni qo'shish algoritmi:

  1. Qavslarni oching.
  2. O'xshash hadlarni (bir xil harf qismlilarni) birgalikda yig'ing.
  3. Standart ko'rinishga keltirib yozing.

Ko'phadlarni ayirish: Ayiriluvchining har bir hadidan ayiradigan ko'phadning mos hadini ayiramiz. Bu amalda ikkinchi ko'phadning barchа hadlari ishorasini almashtirish bilan tengdir: (A)−(B)=A+(−B).(A) - (B) = A + (-B).

Yechilgan misollar

1-misol. Ko'phadlarni qo'shish

(2x2+3x−1)+(x2−x+4)(2x^2 + 3x - 1) + (x^2 - x + 4) ni soddalashtiring.

  • Qavslarni ochamiz: 2x2+3x−1+x2−x+42x^2 + 3x - 1 + x^2 - x + 4.
  • O'xshash hadlarni yig'amiz:
    • x2x^2 lar: 2x2+x2=3x22x^2 + x^2 = 3x^2.
    • xx lar: 3x−x=2x3x - x = 2x.
    • Sonlar: −1+4=3-1 + 4 = 3.
  • Javob: 3x2+2x+33x^2 + 2x + 3.

2-misol. Ko'phadlarni ayirish

(5a2−2a+3)−(2a2+a−1)(5a^2 - 2a + 3) - (2a^2 + a - 1) ni soddalashtiring.

  • Ikkinchi ko'phadning barcha ishoralarini almashtirish: 5a2−2a+3−2a2−a+15a^2 - 2a + 3 - 2a^2 - a + 1.
  • O'xshash hadlar:
    • a2a^2: 5a2−2a2=3a25a^2 - 2a^2 = 3a^2.
    • aa: −2a−a=−3a-2a - a = -3a.
    • Sonlar: 3+1=43 + 1 = 4.
  • Javob: 3a2−3a+43a^2 - 3a + 4.

3-misol. Uch ko'phadni qo'shish

(x2−3)+(2x+5)+(−x2+2x−2)(x^2 - 3) + (2x + 5) + (-x^2 + 2x - 2) ni soddalashtiring.

  • Qavslarni ochamiz: x2−3+2x+5−x2+2x−2x^2 - 3 + 2x + 5 - x^2 + 2x - 2.
  • x2x^2: x2−x2=0x^2 - x^2 = 0.
  • xx: 2x+2x=4x2x + 2x = 4x.
  • Sonlar: −3+5−2=0-3 + 5 - 2 = 0.
  • Javob: 4x4x.

4-misol. Qiymat topish

A=3m2−2m+1A = 3m^2 - 2m + 1 va B=m2+m−3B = m^2 + m - 3 bo'lsa, A−BA - B ni m=2m = 2 da hisoblang.

  • Avval A−BA - B ni soddalashtiring: (3m2−2m+1)−(m2+m−3)=2m2−3m+4(3m^2 - 2m + 1) - (m^2 + m - 3) = 2m^2 - 3m + 4.
  • Endi m=2m = 2 qo'yamiz: 2⋅4−3⋅2+4=8−6+4=62\cdot4 - 3\cdot2 + 4 = 8 - 6 + 4 = 6.
  • Javob: 6.

Mashq

  1. (3x+5)+(2x−3)(3x + 5) + (2x - 3) ni soddalashtiring.
  2. (a2+2a−1)+(3a2−a+4)(a^2 + 2a - 1) + (3a^2 - a + 4) ni hisoblang.
  3. (7b−2)−(3b+4)(7b - 2) - (3b + 4) ni soddalashtiring.
  4. (4x2−x+2)−(x2−3x−1)(4x^2 - x + 2) - (x^2 - 3x - 1) ni soddalashtiring.
  5. A=2n2−n+3A = 2n^2 - n + 3 va B=n2+n−1B = n^2 + n - 1 uchun A+BA + B ni toping.
  6. Yuqoridagi AA va BB uchun A−BA - B ni toping.
  7. (p3−p+2)+(p2−p3+p−2)(p^3 - p + 2) + (p^2 - p^3 + p - 2) ni soddalashtiring.
  8. (5t2−3t+1)−(5t2+3t−1)(5t^2 - 3t + 1) - (5t^2 + 3t - 1) ni hisoblang.
  9. Ko'phad P=x2−3x+cP = x^2 - 3x + c da x=2x = 2 da P=3P = 3 bo'lsa, cc ni toping.
  10. (2a−b)+(3b−a)−(a+2b)(2a - b) + (3b - a) - (a + 2b) ni soddalashtiring.
Javoblar va yechim yo'llari
  1. (3+2)x+(5−3)=5x+2(3+2)x + (5-3) = 5x + 2.
  2. (1+3)a2+(2−1)a+(−1+4)=4a2+a+3(1+3)a^2 + (2-1)a + (-1+4) = 4a^2 + a + 3.
  3. (7−3)b+(−2−4)=4b−6(7-3)b + (-2-4) = 4b - 6.
  4. (4−1)x2+(−1+3)x+(2+1)=3x2+2x+3(4-1)x^2 + (-1+3)x + (2+1) = 3x^2 + 2x + 3.
  5. (2+1)n2+(−1+1)n+(3−1)=3n2+2(2+1)n^2 + (-1+1)n + (3-1) = 3n^2 + 2.
  6. (2−1)n2+(−1−1)n+(3+1)=n2−2n+4(2-1)n^2 + (-1-1)n + (3+1) = n^2 - 2n + 4.
  7. p3−p3=0p^3 - p^3 = 0; p2p^2; −p+p=0-p + p = 0; 2−2=02 - 2 = 0. Javob: p2p^2.
  8. 0−6t+2=−6t+20 - 6t + 2 = -6t + 2.
  9. 4−6+c=3⇒c=54 - 6 + c = 3 \Rightarrow c = 5.
  10. 2a−a−a=02a - a - a = 0; −b+3b−2b=0-b + 3b - 2b = 0. Javob: 00.

Keng tarqalgan xatolar

1. Ayirganda ichki qavsni ochishni unutish (ishora almashmaslik). ✗ (5a−2)−(3a+4)=5a−2−3a+4=2a+2(5a - 2) - (3a + 4) = 5a - 2 - 3a + 4 = 2a + 2. ✓ 5a−2−3a−4=2a−65a - 2 - 3a - 4 = 2a - 6. (Minus qavs oldida — barcha ishoralar almashadi.)

2. O'xshash bo'lmagan hadlarni qo'shish. ✗ 3x2+2x=5x23x^2 + 2x = 5x^2. ✓ 3x2+2x3x^2 + 2x — bu allaqacha sodda; x2x^2 va xx — farqli.

3. Ko'phadning darajasini noto'g'ri aniqlash. ✗ 3x4−2x3+x3x^4 - 2x^3 + x ning darajasi 3+4=73+4 = 7. ✓ Daraja — eng katta ko'rsatkich: 44.

4. Standart ko'rinishni teskari yozish. ✗ 1−2x+3x21 - 2x + 3x^2 — daraja o'sish tartibida. ✓ 3x2−2x+13x^2 - 2x + 1 — daraja kamayish tartibida.

5. Nol had hosil bo'lganda uni tark etmaslik. ✗ x2−x2+2x=x2+2xx^2 - x^2 + 2x = x^2 + 2x. ✓ 0+2x=2x0 + 2x = 2x.

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Test

0 / 5 javob berildi

  1. 1.(3x2−2x+1)+(x2+4x−3)(3x^2 - 2x + 1) + (x^2 + 4x - 3) ning yig'indisi?

  2. 2.(5a−3b)−(2a+b)(5a-3b) - (2a+b) ni soddalashtiring.

  3. 3.2x3−x+42x^3 - x + 4 ko'phadining darajasi?

  4. 4.2x2−5x+32x^2 - 5x + 3 ko'phad nechta haddan iborat va uning darajasi nechaga teng?

  5. 5.(4m2−3m+2)−(m2−3m−5)(4m^2 - 3m + 2) - (m^2 - 3m - 5) ni hisoblang.